2[2x-(3x-8)]=9(x-8)

Solution for 2[2x-(3x-8)]=9(x-8) equation:

Simplifying
2[2x + -1(3x + -8)] = 9(x + -8)

Reorder the terms:
2[2x + -1(-8 + 3x)] = 9(x + -8)
2[2x + (-8 * -1 + 3x * -1)] = 9(x + -8)
2[2x + (8 + -3x)] = 9(x + -8)

Reorder the terms:
2[8 + 2x + -3x] = 9(x + -8)

Combine like terms: 2x + -3x = -1x
2[8 + -1x] = 9(x + -8)
[8 * 2 + -1x * 2] = 9(x + -8)
[16 + -2x] = 9(x + -8)

Reorder the terms:
16 + -2x = 9(-8 + x)
16 + -2x = (-8 * 9 + x * 9)
16 + -2x = (-72 + 9x)

Solving
16 + -2x = -72 + 9x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9x' to each side of the equation.
16 + -2x + -9x = -72 + 9x + -9x

Combine like terms: -2x + -9x = -11x
16 + -11x = -72 + 9x + -9x

Combine like terms: 9x + -9x = 0
16 + -11x = -72 + 0
16 + -11x = -72

Add '-16' to each side of the equation.
16 + -16 + -11x = -72 + -16

Combine like terms: 16 + -16 = 0
0 + -11x = -72 + -16
-11x = -72 + -16

Combine like terms: -72 + -16 = -88
-11x = -88

Divide each side by '-11'.
x = 8

Simplifying
x = 8